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#71 | ||||||
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Stalker
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Iam Flatline Legion Soc: SoF-Cadets
Location: Sweden
EFD: 466.19
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#72 | ||||||
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Reborn
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When I remember right, then Aurlis do loot quite often, more than Atrox. So they have a lower empty rate. Since they loot more often, loot should be lower to get the same mean from them. If this is the case, then this would be an indication that also global loot must be empty corrected before analysis, as we already know from normal loot.
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#74 | |||||||
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Reborn
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Mix Exp Poisson With this approach every loot value is regarded as a single species independent form all other species. The frequency of one loot value is modeled as an poisson random variable with mean m. The means mi of the different loot values are then modeled by an exponential or mixture of exp distributions. They do the mixture only to achieve a better fit. So there is no interpretation given. I'm not sure if this approach fits our situation, but for those that like discrete distributions this might be an interesting idea. |
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#75 | ||||||
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Dominant
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When you say mean Mi, you mean that every loot is exponential with a different parameter (mean)?
If they all have the same mean, the sum of all loots in a hunt would be distributed Erlang with parameters (mean, number of mobs looted). And again I say, I find the assumption of each loot being independent of the previous very problematic. I know that intuition plays tricks on you when it comes to probability but still. I can not think of a way to check this assumption though. |
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#76 | |||||||
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Dominant
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#77 | |||||||
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Reborn
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I guess it goes the other way around. From the observed data you build i classes. The count (number of loots) of each class is poisson distributed with mean mi (expected number of events during a specified time period). So every class can have it's own mean. The means mi itself are exponentially distributed or more generally follow a mixture of exp. distributions (hyper-exponential, phase-type dist). In letting the counts of a single class being poisson distributed you model the observation time. This is not the case with my approach. Counts within classes are iid from other classes, but since the mean do follow a mix exp you model indirectly a dependency. Last edited by falkao; 04-23-2008 at 12:47. Reason: typos |
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#79 | ||||||
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Reborn
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here some further testing on ambus with an exp mixture.
if I use a 2 phase model and assume truncation at 50 PED (so not a shift by 50) I get the following estimates. (I changed from MLE to EM estimation, but thats only for those that are interested how to estimate). Code:
m2 = p m pt pe 0.05108 226.02 0.8015 0.01764 0.94892 37.912 0.2674 0.98235 With the 2 phase model we get one exp with mean 37.9 and a relative frequency within global loot of 95%. The second has mean 226 and a rel. freq of 5%. An exp dist. with mean 37.9 would have about 27% of all observations after the truncation point of 50 PED. For the second dist this is 80%. So for every dist we have pt_i * pe_i = p_i this can be resolved to pe_i = p_i/pt_i * n where n is a normalizing constant and is equal to sum(p_i/pt_i). This gives the above depicted pe. So the real rel. frequency of the first dist. with mean 37.9 is 98% and that of the second with mean 226 is 2%. So what does that mean? If the assumption "that we observe truncated data" is right, then there are two loot distributions. The first has mean 37.9 PED and is triggered in 98% of cases. Only about 27% of the values from dist dist lead tio globals. The second has mean 226 and is triggered in about 2% of all loots. About 80% of the values from this dist. lead to globals. So it looks as we are able to estimate from global loot also one part of the non observable loot. One further thing. It might be that MA sets an upper limit. With an exp distribution you would be able to generate an infinity high loot. Therfore I guess they truncate the propability at .001 or .0001. The respective multipliers would be abou 7 and 9. So maximally 259-333 PED would be generated by the first dist and 1582-2034 from the second. Loot expectation for the m2 model is 41.23 PED For a 3 phase model I get the following: Code:
m3 = p m pt pe 0.65368 57.103 0.4166 0.17237 0.34144 16.164 0.0453 0.82706 0.00488 957.13 0.9491 0.00056 Loot expectation for the m3 model is 23.75 PED |
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#80 | |||||||
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Old
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Wish I had more time to help with this. Hopefully this summer. |
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